Question

5.
Find the ratio of the number of atoms present in
16 g of O, to 16 g of Og.
(1) 1:1
(2) 2:1
(3) 1:3
(4) 1:2
​

Answer 1

Answer:

Number of atom = moles x Avogadro's number x atomicity

Moles of 02 = 16/32 =1/2

Moles of 03 = 32/48 =2/3

No. of atom of 02/ No. of atom of O3 =(1/2 x Na x 2)/(2/3 x Na x 3)

Ratio will be=1/2 ...... (4) Here Na = Avogadro's number

atomicity = total number of atom present in a molecule.