Question

5. Find the roots of the equation 2x²-5x+3=0 using formula​

Answer 1

Answer:

2x²-5x+3=0

2x²-2x-3x+3=0

2x(x-1)-3(x-1)=0

(2x-3)(x-1)=0

x=3/2, 1

Step-by-step explanation:

hope it is helpful

Answer 2

$\color{crimson} { \boxed{\sf roots =  \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }}$

$\purple{ \sf here : }$

• $\sf a = 2$
• $\sf b = - 5$
• $\sf c = 3$

$\implies \sf roots = \frac{ - ( - 5)± \sqrt{ {( - 5)}^{2} - 4(2)(3) } }{2(2)}$

$\implies \sf roots = \frac{ 5± \sqrt{ 25 -24 } }{4}$

$\implies \sf roots = \frac{ 5± \sqrt{ 1} }{4}$

$\implies \sf roots = \frac{ 5± 1}{4}$

$\purple{ \sf case(1) :}$

$\sf root(x) = \frac{5 + 1}{4}$

$\implies \sf root = \frac{6}{4}$

$\boxed{\orange{ \sf \therefore root = \frac{3}{2} }}$

$\purple{ \sf case(2) :}$

$\sf root(x) = \frac{5 - 1}{4}$

$\implies \sf root = \frac{4}{4}$

$\boxed{ \orange{ \therefore \sf root = 1 }}$

$\sf therefore ;$

$\sf roots \: of \: equation \: \red{2 {x}^{2} - 5x + 3 = 0 } \: are$

$\sf \color{darkblue}{\frac{3}{2} \: \: \color{black}{and } \color{darkblue}\: \: 1}$