Question

5. Find the roots of the following quadratic
equation :
(x + 3)(x - 1) = 3(x -1/3 )​

Answer 1

hope it helps you.....

Answer 2

Step-by-step explanation:

(x + 3) (x - 1) = 3(x - 1/3)

=> x^2 - x + 3x - 3 = 3x - 3 / 3

=> x^2 + 2x - 3 = 3x - 3/3

=> 3 (x^2 + 2x - 3) = 3x - 3

=> 3x^2 + 6x - 9 = 3x - 3

=> 3x^2 + 6x - 3x - 9 + 3 =0

=> 3x^2 + 3x - 6 = 0

=> 3 (x^2 + x - 2) = 0

=> x^2 + x - 2 = 0

=> x^2 + (2-1) x - 2 = 0

=> x^2 + 2x - x - 2 = 0

=> x (x + 2) - 1 (x + 2) = 0

=> (x + 2) (x - 1) = 0

either, x = -2

or, x = 1

hope it helps u mate.. if you think it's worthy then pls do mark as brainliest