Question

5. Find the smallest square number that is divisible by each of the numbers 8,15 and 20. ​

Answer 1

Answer:

3,600

Step-by-step explanation:

find LCM of 8,15 and 20

8=2×2×2

15=3×5

20=2×2×5

So, LCM =2×2×2×3×5=120.

For nos which are not in pairs in LCM factors, we need to multiply 120 by 2, 3 and 5 to make it a perfect square.

Required Number =120×2×3×5=3600

Answer 2

Answer: 3600

Step-by-step explanation:

8= 2x2x2

15= 3x5

20= 2x2x5

LCM= 2x2x2x3x5= 120

120x2x3x5= 3600 (Multiply the no.s which are not in pairs to make it a perfect square.)

The smallest square number that is divisible by 8, 15 and 20 is 3600.