Question

5. Find the smallest square number which is divisible by each of the number 9, 10, 12, and 15.​

Answer 1

Correct answer:-

Refer to the attachment.

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Answer 2

Answer:

Step-by-step explanation:

Hey there!

Since, we wanted  the smallest perfect square number divisible by 6, 9 and 15.

So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.

Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).

= 90 × 2 × 5

= 90 × 10

= 900

Hence,

Required smallest square no. that's divisible by 6, 9 and 15 = 900

SOLUTION IN THE BELOW PIC. IS ALSO FOR REFERENCE

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