Question

5
Find the sum of all natural numbers
from Ito 200 , which are divisible by 3.





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Answer 1

Step-by-step explanation:

1+2+3+4+.........n

[n(n+1)]/2

then

1+2+3+4+........200

we found that n=200

so

200(200+1)/2

=200×201/2

=100×201

=20100 is the sum of natural number 1to 200

Answer 2

Answer:

20100 is your answer dear:)

Step-by-step explanation:

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