5. Find the two numbers whose difference, sum and product are in the ratio
- 2:3:5.
Answers
Answered by
0
Answer:
0or27
Step-by-step explanation:
We let the two numbers be x and y.
So,
x−yx+yxy=k=7k=18k
Adding the first two equations,
2x=8k⟹x=4k
Subtracting the two equations now,
−2y=−6k⟹y=3k
Thus,
xy=(4k)(3k)=12k2
But this is also equal to 18k, so:
12k2=18k
2k2=3k
k(2k−3)=0
Therefore,
k=0 or 32
So,
xy=18k=0 or 27
Answered by
2
Answer:
10 and 2
Step-by-step explanation:
according to the given condition,
x-y:x+y:xy=2:3:5
solving simultaneously we get x = 5/2 and y =1/2
xy=5k; k is constant
5/2k*1/2k=5k
5/4=5k
k=20/5
k=4
x=5/2k= 5/2*4= 10
y=1/2k=1/2*4=2
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