Math, asked by shubhangiranadhir, 3 months ago

5. Find the two numbers whose difference, sum and product are in the ratio
- 2:3:5.​

Answers

Answered by s15797bsomya03183
0

Answer:

0or27

Step-by-step explanation:

We let the two numbers be x and y.

So,

x−yx+yxy=k=7k=18k

Adding the first two equations,

2x=8k⟹x=4k

Subtracting the two equations now,

−2y=−6k⟹y=3k

Thus,

xy=(4k)(3k)=12k2

But this is also equal to 18k, so:

12k2=18k

2k2=3k

k(2k−3)=0

Therefore,

k=0 or 32

So,

xy=18k=0 or 27

Answered by muddpraku00
2

Answer:

10 and 2

Step-by-step explanation:

according to the given condition,

x-y:x+y:xy=2:3:5

solving simultaneously we get x = 5/2 and y =1/2

xy=5k; k is constant

5/2k*1/2k=5k

5/4=5k

k=20/5

k=4

x=5/2k= 5/2*4= 10

y=1/2k=1/2*4=2

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