Question

5. Find the value of:
(a) x + y + z3 - 3xyz if x = 1, y = 2 and z = 3​

Answer 1

Answer:

x =1

y = 2

z = 3

so , substituting ,,

x +y +z3 -3xyz

1+2+(3)^3 -3(1)(2)(3)

1+2+27 - 18

30 -18

= > 12

Step-by-step explanation:

hope it helps you

mark as brainliest

Answer 2

Answer:

x + y + z3 - 3xyz

= 1 + 2 + (3) ^3 - 3(1) (2) (3)

= 1 + 2 + 27 - 18

= 30 - 18

= 12