Question

5) find the value of iii) sec^2 60° - tan^2 60° ​. with solution​

Answer 1

$\tt \huge \bigstar{answer : } \\ \\ \tt \: sec \: 60 = 2 \\ \\ \tt \: tan \: 60 = \sqrt{3} \\ \\ \sf \huge \implies \: se {c}^{2} 60 - {tan}^{2} 60 = {2}^{2} - { \sqrt{3} }^{2} = 4 - 3 = 1$

Answer 2

Answer:

answer - → 1 .

method 1.

since,

sec²∅ - tan²∅ = 1

so,

sec ²60° - tan²60° = 1

as,

∅ = 60°.

Step-by-step explanation:

method 2..

since sec60° = 2

and tan30° = √3

so,

sec²60^ - tan²60°

= 2² - {√3} ²

= 4 -3

= 1..

I hope it will help you..