Question

5. Find the value of k for which the equation
3.x2 - 6x + k = 0 has distinct and real root.​

Answer 1

EXPLANATION.

Quadratic equation.

⇒ 3x² - 6x + k = 0.

As we know that,

⇒ D = Discriminant Or b² - 4ac.

For real and equal roots : D = 0.

⇒ (-6)² - 4(3)(k) = 0.

⇒ 36 - 12k = 0.

⇒ 12k = 36.

⇒ k = 3.

                                                                                                                       

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.