Math, asked by llEmberMoonblissll, 17 hours ago

5. Find the value of k, such that the number
given against each equation is one of its roots:
(i) x2 + kx - 21 = 0; 3
(ii) x2 + kx - 5 = 0; 1
(iii) x2 + 12x + k = 0; -5​

Answers

Answered by MrFeast
2

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2k + 5 = 105 \\ 2k = 105 - 5 \\ 2k = 100 \\ k =  \frac{100}{2}  \\ k = 50

Answered by krishhhhnna
1

Answer:

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