Question

5) Find the value of Theta, if
3 tan^2 (theta-10)=1​

Answer 1

Answer:

3

(tan2θ+tan3θ)=1−tan2θtan3θ

⇒

1−tan2θtan3θ

tan2θ+tan3θ

=

3

1

⇒tan5θ=

3

1

⇒tan5θ=tanπ/6

⇒5θ=nπ+π/6⇒θ=

5

1

(nπ+π/6)=(n+

6

1

)π/5