Question

5. Find the value of y for which the distance between the points A(3,-1) and B(11,y)
is 10 units.​

Answer 1

Answer:

solving by distance formula

Step-by-step explanation:

ab Square=(11-3)square+(y+1)square=100

64+y square+1+2y=100

y square+2y-35=0

y square-5y+7y-35=0

y(y-5)+7(y-5)=0

(y-5) (y+7)=0

y=5,y=7

Answer 2

Step-by-step explanation:

A(3,-1),B(11,y)

distance formula=√((x2-x1)^2+(y2-y1)^2)

here,x1=3

x2=-1

y1=11

y2=y

distance is given as 10 units

so,

10=√((-1-3)^2+(y-11)^2)

10=√((-4)^2+y^2+11^2-2(y)(11))

10= √(16+y^2+121-22y)

squaring on both sides

10^2=y^2+137-22y

y^2-22y+37=0

solve the quadratic equation

we get,

y=some answer