Question

5 Find the zeros of the quadratic polynomial
f(x) = abx? + (62 - ac) * - bc,​

Answer 1

Answer:

Answer

Given: abx

2+(b2−ac)x−bc=0

Factorizing the given equation,

⟹abx

2+b2

x−acx−bc=0

⟹bx(ax+b)−c(ax+b)=0

⟹(bx−c)(ax+b)=0

Solving the above equation for x, we get

⟹(bx−c)=0 or (ax+b)=0

⟹x=bc or x= a−b