5.
Find three consecutive numbers such that if they are divided by 10, 17, and 26 respectively,
the sum of their quotients will be 10.
X
x+1 x+2
10 17 26
(Hint: Let the consecutive numbers = x,x+1,x+2, then
+
+
=10)
Answers
Answer:
Let X, (X+1), (X+2) are 3 consecutive numbers.
X/10 + (X+1)/17+ (X+2)/26 =10
L.C.M = 4420
(442(X) +260(X+1) +170(X+2))/4420=10
(442x+260x+260+170x+340)= 4420×10
(442x+260x+170x+260+340)=44200
872x + 600= 44200
872x= 44200- 600
872x= 43600
X= 43600/872
X= 50
Ist no. (X)= 50
2nd no.(x+1)= 50+1= 51
3rd no.(x+2)= 50+2= 52
The 3 consecutive numbers are 50, 51, 52
Answer:
Step-by-step explanation:
Let X, (X+1), (X+2) are 3 consecutive numbers.
X/10 + (X+1)/17+ (X+2)/26 =10
L.C.M = 4420
(442(X) +260(X+1) +170(X+2))/4420=10
(442x+260x+260+170x+340)= 4420×10
(442x+260x+170x+260+340)=44200
872x + 600= 44200
872x= 44200- 600
872x= 43600
X= 43600/872
X= 50
_____________________________
Ist no. (X)= 50
2nd no.(x+1)= 50+1= 51
3rd no.(x+2)= 50+2= 52
____________________________
The 3 consecutive numbers are 50, 51, 52
_____________________________
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