5. Find three consecutive numbers such that sum of the first and second is 45 more than the third number.
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Let the number be x , x+1 ,x+2
Sum of first and second number is 45
A/ q
X+(x+1)= 45
2x= 45–1= 44
X= 44/2= 22
First number =22
Second number=22+1=23
Third number= 22+2=24
Please mark it as brainlist answer.
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