Question

5. Find three different solutions for each of the
following equations :
(1) 5x + 3y = 4 (i) + 4y = 6
(iii) 3y -5=0 please answer me with step by step solution​

Answer 1

Explanation:

$\huge{\underline{\underline{Given→}}}$

• $\sf\green{Equation\:1=5x+3y=4}$
• $\sf\green{Equation\:2=4y=6}$
• $\sf\green{Equation\:3=3y-5=0}$

$\huge{\underline{\underline{To\:Find→}}}$

$\sf\pink{→Solutions\:of\:the\:given\:equations\:}$

$\huge{\underline{\underline{Answer→}}}$

$\bold{\underline{For\:Equation\:1→}}$

$→5x+3y=4$

$→5x=4-3y$

$→x=\frac{4-3y}{5}$

$→Putting\:y=1$

$→x=\frac{4-3}{5}$

$→x=\frac{1}{5}$

$\sf{\boxed{\boxed{\red{→x=\frac{1}{5}✔}}}}$

$→Putting\:y=0$

$→x=\frac{4-0}{5}$

$→x=\frac{4}{5}$

$\sf{\boxed{\boxed{\red{→x=\frac{4}{5}✔}}}}$

$→Putting\:y=-2$

$→x=\frac{4+6}{5}$

$→x=\frac{10}{5}$

$→x=2$

$\sf{\boxed{\boxed{\red{→x=2✔}}}}$

$\bold{\underline{For\:Equation\:2→}}$

$→4y=6$

$→y=\frac{6}{4}$

$\sf{\boxed{\boxed{\red{→y=\frac{6}{4}✔}}}}$

$\bold{\underline{For\:Equation\:3→}}$

$→3y-5=0$

$→y=\frac{5}{3}$

$\sf{\boxed{\boxed{\red{→y=\frac{5}{3}✔}}}}$

HOPE IT HELPS.

Answer 2

Answer:

$\huge\bigstar\underline\mathfrak{Question:-}$

5. Find three different solutions for each of the

following equations :

(1) 5x + 3y = 4 (i) + 4y = 6

(iii) 3y -5=0

$\huge\bigstar\underline\mathfrak{Answer:-}$

Please refer to above attachment.