Question

5. Find three numbers such that, the second is twice
the first, the third is three times the first and their
sum is 180.​

Answer 1

Answer:

let 1st no. be x , then

2nd no. = 2x

3rd no. = 3x

according to Q :

x +2x +3x = 180

6x = 180

x = 180/6

x = 30

so, 1st no. = 30

2nd no. = 2×30 = 60

3rd no. = 3×30 = 90

verification : 30+60+90 = 180