5. Find two numbers such that the sum of twice the first and thrice
the second is 92, and four times the first exceeds seven times the second
by 2.
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Answer:
let two numbers be x,y.
given,
2x+3y=92.
4x-7y=2
13y=182
y=14
x=25
so the numbers are 25 and 14.
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