Question

5 Find two numbers such that the sum of twice the first and thrice the
second is 92, and four times the first exceeds seven times the second
by 2.​

Answer 1

Answer:

2 and six so it is help you same

Step-by-step explanation:

plz

Answer 2

Let x and y be the two numbers.

2x + 3y = 92. -----eqn i

4x = 7y + 2

4x - 7y = 2. -----eqn ii

4 * eqn (i):

8x + 12y = 368. ---- eqn iii

2 * eqn (ii):

8x - 14y = 4. ---eqn iv

eqn (iii) - eqn (iv):

26y = 364

y = 364/26

= 14

Substituting in eqn (ii):

4x - 7(14) = 2

4x - 98 = 2

4x = 2 + 98

= 100

x = 100/4

= 25

Therefore, the numbers are:

x = 25 and y = 14

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