Question

5. Five trees were planted on one side of a road
at equal intervals. If the distance between two
consecutive trees be 2 1/3 m, find the distance
between the first and the fifth tree.​

Answer 1

Answer:

Step-by-step explanation:

Let the trees stand at points A, B, C, D and E

We know that AB=BC=CD=DE= 2 1/3 m

2 1/3 = 7/3

So, Distance between A and E that is AE= AB+BC+CD+DE

or 4 * AB = AE

= 4 * 7/3 =  28/3 m

Therefore, the distance between the first and last tree is 28/3 metres

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Answer 2

Answer:

the distance between 1 and second trees =21/3=7m

the distance between 1and 5 = 7×4

=28m

Step-by-step explanation:

we have taken 4 tree because if we count from 1 to 2is 7 then 2to 3 is 7 and 3to4 is 7 and 4 to 5is 7

when we add this it will be 28