Question

5.
For a particle, thrown from the ground obliquely.
ū= (51 +6j)ms "a = (0i-101) ms where x
and y axes are in horizontal and vertical directions
respectively. The horizontal range of the particle, is
(1) 12 m
(2) 3 m
BY 6 m
(4) 10 m​

Answer 1

Answer:

The horizontal range of the particle, is 6 m

Step-by-step explanation:

particle, thrown from the ground

ū= (5i +6j)ms

a = (0i-10j)

Vertical Velocity = 6

Vertical acceleration = -10

Time to reach Peak =  (0-6)/(0-10) = 6/10  =  0.6

Time of Flight = 2 * 0.6 = 1.2

Horizontal Velocity = 5

The horizontal range of the particle = 5 * 1.2  = 6 m

The horizontal range of the particle, is 6 m