Physics, asked by nivedhabhaskar25, 10 months ago

5.)for a projectile thrown with a speed of 50 metre per second at an angle 37 degree with the horizontal the time of flight will be (g=10 metre per second square )

a. 8 s
b. 6 s
c. 4 s
d. 2 s​

Answers

Answered by technicalaliin
4

Explanation:

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Answered by tripathishashank872
5

Explanation:

formula for time of flight of a projectile is 2usin(x)/g

u=50m/s

g=10

T= 2(50)sin(37)/10

= 10(sin37°)

= 10(3/5)

= 6seconds .

Time of flight is 6secs

note:- VALUE OF sin37° ARISES FROM THE PYTHAGOREAN TRIPLET (3,4,5) . THEREFORE THE VALUE OF sin37° is 3/5 and cos37° is 4/5. .

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