Question

5) for a transistor, lc=15Ma , IB = 0.5 mA, find value of cornent
amplification factor

Answer 1

Answer:

Given : α=0.95 I

b

=0.2 mA

Current gain β=

1−α

α

∴ β=

1−0.95

0.95

=19

Thus collector current I

c

=βI

b

∴ I

c

=19×0.2=3.8 mA

Emitter current I

e

=

α

I

c

∴ I

e

=

0.95

3.8

=4 mA

Explanation:

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