Question

5. For combustion of 1 mole of benzene at 25°C, the heat of reaction at constant pressure is -780.9
kcal. What will be the heat of reaction at constant volume?
CH()+7-0219) – 6CO2(g) + 3H2O()
a. -781.8 kcal 6.-780.0 kcal c . +781.8 kcal d.+780.0 kcal
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Answer 1

Hello dear,

please mention phase of benzene and water...

it is required for calculate this question..

I give you hint....

dH = dE + (dn)RT

dH = heat of reaction at constant pressure

dE = heat of reaction at constant volume

dn = difference of product mole and reactant mole (only gas phase)

R = gas constant

T = temperature (in K)

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