Question

5. For equal root, kx(x - 2) + 6 = 0,
the value of kis
O a) k = 0, -6
O b) k = 6
O c) k = 0,6
O d) k = 2, 3​

Answer 1

Step-by-step explanation:

Given equation is: kx(x−2)+6=0

kx

2

−2kx+6=0

Then a=k,b=−2k,c=6

Then b

2

−4ac=0

So (−2k)

2

−4k(6)=0

4k

2

−24k=0

4k(k−6)=0

k=0 and k=6