Question

5. For the reaction H.(g) + CO. (g) = CO(g) + H2O(g), if the initial concentration of (H) = (CO) and
x moles/litre of hydrogen is consumed at equilibrium, the correct expression of K, is :-
x²
(1) ²
x
(1+x)
(2) 11 - x²
(3
(3) (2 + x²
(4)
C​

Answer 1

Answer:

Explanation:

We Have :-

H₂(g) + CO₂(g) ⇆ CO(g) + H₂O(g)

Initial Concentration [ H ] = [ CO ]

To Find :-

Correct expression of K

Solution :-

Δm = ( Number of Moles of Products ) - ( Number of Moles of Reactants )

= 2 - 2 = 0

Kp = Kc ( RT )^Δm

Kp = Kc

  H₂ + CO₂  ⇆ CO + H₂O

  a        a           0       0

a(1-x)   a(1-x)      ax      ax

$Kc=\frac{[CO][H2O]}{[H2][CO2]}\\\\= \frac{(ax)(ax)}{[a(1-x)][a(1-x)]}\\ \\= \frac{x^{2} }{(1-x)^{2} }$