Question

5) For what value of k, are the roots of the quadric
equation 3x ²+2 k+ 27=o real ang equal​

Answer 1

Step-by-step explanation:

is roots are equal then D=0

D= b^2-4ac=0

=(2k)^2-4(3)(27)=0

=4k^2-12×27=0

4k^2=12×27

k^2=3×27

K=√3×27

K=√3×3×3×3

=9

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