Question

5. Force F on a particle moving in a straight line
varies with distance d as shown in the figure. The
work done on the particle during its displacement
of 12 m is
[AIPMT (Prelims)-2011]
AF (N)
d(m)
12
7
0 3
(1) 13 J
(3) 21 J
(2) 18 J
(4) 26 J​

Answer 1

Answer:

answer is 15 joule option 3

Answer 2

Answer:

The work done by the particle during its displacement of 12 m is 13 J.

Explanation:

Given: Force = F

 displacement = d (values as shown in attached file)

To find: The work done during the given displacement.

Solution: #For work done, we know that:

            W = Area of force-displacement graph

So, we find the area of force-displacement graph for the numerical values of work done.

           Area = area of rectangle + area of triangle

[Refer to the attached image]

           Area = 4 × 2 + 1/2 × 2 × 5

           Area = 8 + 5

           Area = 13 J = Work done

Hence, the work done by the particle during its displacement of 12 m is 13 J.