5 friends live in the same road A, B, C, D, E. The numbers of B, C, D when multiplied together equals 8424. B is a prime number The numbers B,C, D when added equal twice E’s number, and A, C and E are even reast are odd. A’s number is half as much as E’s. The road numbers run from 12 to 222. What is the value of E?
Answers
Given : The numbers of B, C, D when multiplied together equals 8424. B is a prime number
The numbers B,C, D when added equal twice E’s number, and A, C and E are even rest are odd.
A’s number is half as much as E’s.
The road numbers run from 12 to 222.
To Find : The value of E
Solution:
8424 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 13
B * C * D = 8424
Prime numbers 2 , 3 and 13
road numbers run from 12 to 222
Hence B is 13 as B is a prime number
=> C * D = 8424/13 = 648
A, C and E are even
B & D are odd
B = odd = 13
D can be 3 , 9 , 27 , 81 ,
D can be 27 or 81 as road numbers run from 12 to 222
C * D = 648
Hence C can be 24 or 8 so 8 not possible
Hence C = 24 and D = 27
B = 13 , C = 24 , D =27
The numbers B,C, D when added equal twice E’s number,
=> 13 + 24 + 27= 2 ( E)
=> E = 32
A is half of E = 32/2 = 16
Value of E id 32
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given B x C x D = 1260
also B + C + D = 2 x E,
A = E +(E/2)
we can solve this by finding the factor of 1260
again we have a condition that the numbers are between 2 to 222
now group the factors of 1260
There are 36 factors of 1260:
1, 2, 3, 4, 5, 6, 7, 9, 10, 12, 14, 15, 18,20, 21, 28, 30, 35, 36, 42, 45, 60, 70, 84, 90,105, 126, 140, 180, 210, 252, 315, 630, 1260
as per the condition we must use only numbers between 2 & 222
therefore the count is reduced to 29 from 36
2, 3, 4, 5, 6, 7, 9, 10, 12, 14, 15, 18,20, 21, 28, 30, 35, 36, 42, 45, 60, 70, 84, 90,105, 126, 140, 180, 210
now choose appropriate number matches for 1260 from reverse order for ease
210*6 = 210*3*2
by this 6,2,3,210,8
similarly 36,4,9,35,24 also suits
but generalized numbers will be in these multiples as follows
A will be a multiple of 6
B will be a multiple of 2
C will be a multiple of 3
D will be a multiple of 35
E will be a multiple of 8
think so i justified the answer but correct me if any