Question

5. From a point in the interioan equilateral triangle, perpendiculars are
drawn on the three sides. If the lengths of the perpendiculars are a, b and
C, find the area of the triantriang​

Answer 1

Answer:

Area of ∆ABC = Area of ∆APB + Area of ∆BPC + Area of ∆CPA

4

3

a

2

=

2

1

[PS×AB×PQ×BC×PR×AC]

⇒

4

3

a

2

=

2

1

×a×[14×10×6]

⇒

4

3

a

2

=

2

1

×a×30

⇒

4

3

a

2

=15a

⇒a=

3

15×4

=

3

60

cm

Area of triangle ABC =

4

3

×

3

60

×

3

60

=300

3