5
From the top a 50 m
high tower the angle
of the top and bottom of a pole are
observed to be 45 and 60.
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Step-by-step explanation:
in triangle ABC
tan 60 = BC/ AB = 50/AB
√ 3 = 50 / AB
AB = 50/√3
AB = CE = 50/√3
in triangle CDE
tan 45 = DE/ CE
1 = DE / CE
DE = 50/√ 3
AD = DE + AE
= 50 + 50/ √3
= (50√3 + 50 )/√3
=50 ( √3+1) /√3
= 50( 3+√3) /3
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