Question

5 g ice at 0 degree Celsius is mixed with 1 gram steam at hundred degree Celsius find the final temperature and composition of the mixture​

Answer 1

Answer:

Heat energy required for5gm of water at 0

∘

Cto get converted to water at 100

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C is latent heat required + heat required to change its temperature by 100

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=(80⋅5)+(5⋅1⋅100)=900calories.

Now,heat liberated by 5gm of steam at 100

∘

C to get converted to water at 100

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C is 5⋅537=2685 calories

So,heat energy is enough for 5gm of ice to get converted to 5gm of water at 100

∘

C

So,only 900 calories of heat energy will be liberated by steam,so amount of steam that will be converted to water at the same temperature is 900537=1.66g

So,the final temperature of the mixture will be 100°celsius

Thank you hope it helps