Question

5 g of copper was heated from 20°C to 80°C. How much heat energy was used to heat copper?

(specific heat capacity of Copper is 0.092 cal g^-1

°C^-1

Answer 1

Q = ms∆T

Here, m is 5g
s is 0.092
∆T is (80-20) = 60

So, Q is (5)(60)(0.092)

= 27.6 J.....

I'm still in class Xth, so you are welcome to point out any mistakes
.....

Answer 2

Quantity of heat= m×c×(t2-t1)
=5×(80-20)×0.092
=5×60×0.092
=300×0.092
=27.6 cal