Question

5 g of oxygen is produced by heating kclo3 .how much kcl is produced in the reaction

Answer 1

MASS KCL=39.1+35.5= 74.6G/MOL
MOLAR MASS O2 =32G/MOL
MOL O2 PRODUCED=1.5/32=0.0469 MOL 
MASS OF KCL PRODUCED= 0.0313*74.6=2.33G KCL PRODUCED

Answer 2

Answer: 7.76 g KCl is produced in the reaction

Explanation:

$2KCl\overset{\Delta }\rightarrow 2KCl+3O_2$

Amount of oxygen produced is reaction = 5 g

Moles of oxygen produced in the reaction:$\frac{\text{mass of oxygen produced in a reaction}}{\text{molecular mass of oxygen}}=\frac{5 g}{32 g/mol}=0.1562 moles$

As per reaction one mole $KClO_3$ produces one mole of KCl and 3/2 moles of $O_2$.

As per reaction, 3/2 moles of $O_2$ from one mole of $KClO_3$are formed, then 0.1562 moles of $O_2$ will be formed from = $\frac{1}{\frac{3}{2}}\times 0.1562=\frac{1\times 2}{3}\times 0.1562 moles=0.1041 \text{moles of}KClO_3$

If one mole of $KClO_3$ gives one moles of KCl, then 0.1041 moles of$KClO_3$ will give 0.1041 moles of KCl.

Mass of KCl produced= $\text{number of moles of KCl}\times \text{molecular mass of KCl}=0.1041\times 74.55 g/mol=7.76$grams

7.76 g KCl is produced in the reaction