Question

5) Given that 2N02->2NO+02
If the rate of decrease in concentration of NO2is 4.0×10^-13 S^-1,Calculate the rates of increase in concentration of NO and NO2​

Answer 1

Answer:

For the reaction, 2NO

2

→2NO+O

2

−

2

1

dt

d[NO

2

]

=

2

1

dt

d[NO]

=

dt

d[O

2

]

−

dt

d[NO

2

]

=6×10

−12

mol L

−1

s

−1

dt

d[O

2

]

=3×10

−12

mol L

−1

s

−1

.

plz follow me and like this answer