Math, asked by kumar173690, 1 month ago

5. Given that a =(-10). b = 7 and c = (-3). verify
1. a + (b + c) = (a + b) + c
. a x (b + c) = (a x b) + (a x c)​

Answers

Answered by tiwariarnav401
3

Answer:

Verified

Step-by-step explanation:

1. a =-10 ,. b= 7 ,, c= -3

LHS: a+ (b+c) = -10 + (7-3) = -10 + 4 = -6

RHS: (a+b) + c = ( -10 + 7) + (-3) = -3 -3 = -6

hence as LHS =RHS ,

HENCE PROVED .

2. LHS: a× (b+c) = -10 × (7-3) = -10 × 4 = -40

RHS: (a×b) + (a×c) = (-10×7 ) + ( -10×-3) = -70 + 30

= -40

Hence as LHS = RHS

HENCE PROVED

PS. This is also called Distributive property .

Answered by mohit61027
0

Answer:

Step-by-step explanation:

a+(b+c) =(a+b) +c

LHS: a+(b+c)=-10 +(7+(-3))=(-10)+4=-6

RHS: (a+b) +c=(-10+7) +(-3) = -6

hence verified

b)  a x (b + c) = (a x b) + (a x c)​

LHS:  a x (b + c) = -10 * (7-3)=-10* 4=-40

RHS: (a x b) + (a x c)​= (-10*7)+(-10*-3)=-70+30=-40

hence verified

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