Question

5 gram of hydrogen diffuses through a porous membrane in 30 minutes find the time to diffuses the same amount of So2 at identical conditions
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Answer 1

Answer:

The partial pressure of SO2 will be smaller than that of H2, because there will be much less SO2 than H2 molecules. Since pressure is directly proportional to the effusion speed, this means that the speed will be reduced by a factor PM(SO2)/PM(H2)=64/2=32

The SO2 will be moving slower than the H2 at the same temperature. This relation is also directly proportional, but depends on the square root of molecular weight, so the factor will be PM(SO2)/PM(H2)−−−−−−−−−−−−−−−√=32−−√

So we now multiply these two effects, and find that the diffusion speed of SO2 will be 3232−−√ times smaller than that of H2, that is 181 times slower. So it will take 30*181 min for the SO2 to diffuse, that is, about 90 hours.

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