Question

5 gram of water is heated from 20 degree Celsius to 80 degree Celsius . Calculate the amount of heat absorbed by water
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Answer 1

Answer:

Heat energy =mcΔT+mL

where, m = mass of water

c = specific heat capacity of water

L = specific latent heat of fusion of ice

ΔT = change in temperature

Therefore, heat energy released =5×4.2×20+5×336=420+1680 =2100J

Explanation:

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Answer 2

Given:

5 grams of water is heated from 20°C to 80°C

To Find:

The amount of heat absorbed by water.

Solution:

The formula to calculate the heat absorption is

Q = mcΔT, where Q stands for the heat absorbed, m is the mass of the substance absorbing heat, c is the specific heat capacity, and ΔT is the change in temperature.

Now, substitute the values in the formula to find the heat absorbed.

Q = mcΔT+mL

   = 5 × 4.2 × 20 + 5 × 336

   = 420 + 1680

   = 2100J

The amount of heat absorbed by the water is 2100J.