Math, asked by uddeshyagangwar07, 9 months ago


5. Half the perimeter of a rectangular garden, whose length is 4 m more than its width,
36 m. Find the dimensions of the garden.
6. Sriven the linear equation 2x+3y-8=0, write another linear equation in two variabla​

Answers

Answered by anweshakapoor2405
1

Answer:

Step-by-step explanation:

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters.

Answered by sandeepgunwal02
1

Answer:

Let width = x m

then length=x+4 m

perimeter =2(l+b)/2 =36

=l+b=x+x+4 m

2x+4=36

2x=36-4 m

x=32/2 m

x=16 m

x+4=16+4=20 m

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