Question

5 houses in a row are numbered consecutively.. If total of their house numbers is 405, find the greatest house number.. A)105 B)83 C)205 D)73

Answer 1

Answer :-

Let the numbers of houses be x , x + 1 , x + 2 , x + 3 and x + 4

According to the question :-

→ Total of their house numbers = 405

→ x + x + 1 + x + 2 + x + 3 + x + 4 = 405

→ x + x + x + x + x + 1 + 2 + 3 + 4 = 405

→ 5x + 10 = 405

→ 5x = 405 - 10

→ 5x = 395

→ x = 395 / 5

→ x = 79

House numbers :-

• x = 79
• x + 1 = 79 + 1 = 80
• x + 2 = 79 + 2 = 81
• x + 3 = 79 + 3 = 82
• x + 4 = 79 + 4 = 83

Greatest house number = 83

Answer 2

Answer:

Step-by-step explanation: