Question

5. How many atoms of oxygen are present in 50g of CaCO3

Answer 1

Answer:

$\underline{\huge{Answer:-}}$

50g of CaCO3=1. 5∗(6. 022∗1023)=9. 035∗1023 oxygen atoms

Answer 2

Explanation:

M.wt of CaCO

3

=100

number of moles of CaCO_3 present in 50gm =

100

50

=0.5

1 mole of CaCO

3

= 3 moles of O

2

0.5 moles of CaCO

3

has 1.5 moles of oxygen.

1mole=6.022∗10

23

particles

∴ 50g of CaCO

3

=1.5∗(6.022∗10

23

)=9.035∗10

23

oxygen atoms.