5. How many different odd numbers of 4 digits can be formed with the digits 1.2.3.4.5.6.7: the digits in
any number being all different?
(Ans: 480)
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0
Answer:
by adding or what?
please let me know!
Answered by
1
Answer:
given digits
1,2,3,4,5,6,7
odds no's:1,3,5,7
unit place can be filled with any of the four numbers in 4p1 ways
remaining 3 places can be filled with any of the 6(7-1) digits in 6p3 ways
4p1 * 6p3 = 4 * 120 = 480
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