Question

5. How many milligrams are present in 1 ml of 0.05N KMnO4?​

Answer 1

Answer:

52.6g in 1ml of0.05N kmno4

Answer 2

7.9 milligrams are present in 1 ml of 0.05N $KMnO_4$

Explanation:

Normality is defined as the number of gram equivalents dissolved per liter of the solution.

$Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}$

$Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}$

Equivalent weight is calculated by dividing the molecular weight by n factor.  

${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

n= charge on cation , For $KMNO_4$ , n =1

$KMNO_4\rightarrow K^++MnO_4^-$

${\text{Equivalent weight}}=\frac{158g}{1}=158g$

Putting in the values, we get

$0.05=\frac{x\times 1000}{158\times 1ml}$

$x=7.9\times 10^{-3}g=7.9mg$      $1g=1000mg$

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