Question

5. How many moles of Al(SO2), would be present in 50 g of the substance? (Given at volume of Al 21.
S = 32, 0 = 16)
(2) 0.952 mole
(1) 0.083 mole
(4). 0.14 mole
(3) 0.481 mole​

Answer 1

Answer:

0.0952 moles.

Explanation:

means no. of moles = weight / mass

no. of moles= 50/Al(SO4)

= 50/ 21x32x16x2

=2,438.0952.