Math, asked by clmishra3, 5 months ago

(5) How many pieces of marbles, each measuring 5 cm by 5 cm, are required to
3
lay a path 13 m long and 9 m wide ​

Answers

Answered by Anonymous
78

Answer:

Correct Question

How many pieces of marbles, each measuring 5 cm by 5 cm, required to lay a path 13 m long and 9 m wide

To Find

Marble required

Solution

Here we first find area of both path and marble

 \sf \: As \: the \: sides \: are \: same \: of \: marble. \:  \\  \sf \: therefore \: we \: will \: considered \: as \: square.

 \sf \: area \: of \: square \:  =  {side}^{2}

 \sf \: Area \: of \: marble \:  =  {5}^{2}

 \sf \: Area \: of \: marble = 25 \: cm²

Now,

Let's convert the length and breadth into cm.

 \sf \: As \: we \: know \: that

 \huge \bf \:  1 \: m = 100 \: cm

 \sf \: 13 \: m = 13 \times 100 = 1300 \: m

 \sf \: 9 \: m = 9 \times 100 = 900 \: cm

 \sf \: now \: lets \: find \: area \: of \: path

 \sf \: Area \: of \: rectangle \:  = l \times b

 \sf \: Area \: of \: rectangle \:  = 1300 \times 900

 \sf \: Area \: of \: rectangle \:  =  1170000²\: cm

Now,

Let's find Marble required

 \boxed { \bf Total \: marble =  \frac{Area \: of \: path}{Area \: of \: marble}}

 \sf \: Total \: marble \:  =  \dfrac{1170000}{25}

 \sf \: Total \: marble \:  = 46800

 \huge \bf \therefore \: Total \: marble \:  = 46800


Anonymous: Great!
MisterIncredible: Perfect
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