Question

5
How many tiles whose length and
breadthare 12 cm and 5 cm respectively
will be required to fit in a rectangular
floor whose length and breadth are 10
m and 6 m respectively?​

Answer 1

Answer:

$94 \times \frac{2}{17}$

Step-by-step explanation:

Length of tile = 12cm

Breadth of tile = 5cm

Perimeter of tile = 2(l+b)cm = 2(12+5) = 2×17 = 34cm

Length of floor = 10m

Breadth of floor = 6m

Perimeter of floor = 2(l+b) = 2(10+6) = 2×16 = 32m

Therefore,

The number of tiles required are : 3200 cm / 34 cm

$94 \times \frac{2}{17}$

Answer 2

Answer:

100 tiles correct answer pl mark as brainlist