5. How much energy can be consumed by an electric iron of 800 watt, 4 tube lights of 20 watt each
and a refrigerator of 100 watt in a household. What would be the electricity bill for three months if
these appliances are working for 8 hours a day? (The cost of 1 unit of energy is 3.)
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Electricity bill for three months = Rs.2140.32.
Given:
- An electric iron of 800 watt.
- 4 tube lights of 20 watt each.
- Refrigerator of 100 watt in a household.
- Working for 8 hours a day.
- Cost of 1 unit of energy is 3
Find:
Electricity bill for three months.
Explanation:
- All three equipment are working 8 Hr per day hence no need to calculate separate electricity bill of each equipment.
- Each light have 20W hence 4 light has (4×20)W consume energy
- Total household load = 800+(4×20) +100 = 980 W ⇒ 0.98 KW
- For 3 months i.e consider month has (30,31,30)days.
- Hence total 91 days. Per day 8 hr
- For 91 days = 91 × 8 Hr.
= 728 Hr.
- Total load for 3 month = 0.98 × 728
= 713.44 KW/Hr(unit)
- 1 unit energy = 1 KW/Hr cost is 3 rs
- Therefore 713.44 Unit = 713.44 × 3
= 2140.32 Rs.
Electricity bill for three months = Rs.2140.32
To learn more...
1 Write a letter to the electricity board about excessive electric bill.
https://brainly.in/question/7422890
2 CONVERSATION BETWEEN TWO FRIENDS ON PROBLEMS OF ELECTRICITY.
https://brainly.in/question/142854
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