Question

-5. How much pure alcohol must be added to 400 ml of a 15% solution to make its
strength 32%?​

Answer 1

Answer:

60 + x = 128 + 0.32x Subtract 0.32x from both sides. 60 + 0.68x = 128 Subtract 60 from both sides. x = 100 ml of pure alcohol is required.

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Answer 2

Answer:

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Step-by-step explanation:

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