5. (i) (1.5p + 2q)?
Answers
Answer:
qait
Explanation:
2.5p−1.5q)
2
−(1.5p−2.5q)
2
To Find:
Simplify above equation.
Solution:
We know the formula of identity formula:
\mathbf{A^{2}-B^{2}=(A-B)(A+B)}A
2
−B
2
=(A−B)(A+B) ...1)
Now come to question:
\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}}(2.5p−1.5q)
2
−(1.5p−2.5q)
2
...2)
On comparing the equation 1) and equation 2), we get:
A = 2.5 p - 1.5 q
and:
B = 1.5 p - 2.5 q
With help of equation 1):
\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}=(2.5p-1.5q-1.5p+2.5q)(2.5p-1.5q+1.5p-2.5q)}(2.5p−1.5q)
2
−(1.5p−2.5q)
2
=(2.5p−1.5q−1.5p+2.5q)(2.5p−1.5q+1.5p−2.5q) On simplify:
\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}=(p+q)(4p-4q)}(2.5p−1.5q)
2
−(1.5p−2.5q)
2
=(p+q)(4p−4q)
On taking 4 common in second bracket:
\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}=4\times (p+q)\times (p-q)}(2.5p−1.5q)
2
−(1.5p−2.5q)
2
=4×(p+q)×(p−q)
This is answer.