Hindi, asked by nishtha2590, 4 months ago

5. (i) (1.5p + 2q)?​

Answers

Answered by 2005omkumhar
1

Answer:

qait

Explanation:

2.5p−1.5q)

2

−(1.5p−2.5q)

2

To Find:

Simplify above equation.

Solution:

We know the formula of identity formula:

\mathbf{A^{2}-B^{2}=(A-B)(A+B)}A

2

−B

2

=(A−B)(A+B) ...1)

Now come to question:

\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}}(2.5p−1.5q)

2

−(1.5p−2.5q)

2

...2)

On comparing the equation 1) and equation 2), we get:

A = 2.5 p - 1.5 q

and:

B = 1.5 p - 2.5 q

With help of equation 1):

\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}=(2.5p-1.5q-1.5p+2.5q)(2.5p-1.5q+1.5p-2.5q)}(2.5p−1.5q)

2

−(1.5p−2.5q)

2

=(2.5p−1.5q−1.5p+2.5q)(2.5p−1.5q+1.5p−2.5q) On simplify:

\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}=(p+q)(4p-4q)}(2.5p−1.5q)

2

−(1.5p−2.5q)

2

=(p+q)(4p−4q)

On taking 4 common in second bracket:

\mathbf{(2.5p-1.5q)^{2}-(1.5p-2.5q)^{2}=4\times (p+q)\times (p-q)}(2.5p−1.5q)

2

−(1.5p−2.5q)

2

=4×(p+q)×(p−q)

This is answer.

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